A Biomechanical Investigation of Back Shape while Lifting
Friday, April 21, 2017
What is heavy?-Friday April 21st, 2017
After figuring out that it requires less energy, and is safe for your back to perform a stoop lift for a light load, the next logical question is what is heavy? And how long will it take for your lower back to fatigue? This will be different for every person. Originally, I envisioned taking the formula from Garg's method and deriving it, like a maximization problem in calculus. Unfortunately, the formulas from Garg's method are straight lines so calculus doesn't make sense to use. In fact, the stoop lift will always require less energy than the squat lift, but there are weights where the load can only be lifted by performing a squat lift. A second way to determine when a lift is too taxing is by monitoring physiological signs while the subject performs the lift. This is also difficult to do because it requires certain facilities, it is time consuming, and ultimately the results only apply to one person. To avoid this bulky one result process, Snook's Liberty Mutual psychophysical tables were developed. These tables are used in the field of ergonomics to help determine when a job is too physiological demanding to perform. This table is helpful to employers, but it certainly doesn't help the everyday person. So how can you apply this information to everyday life? Well most likely, you don't need a table to tell you when something is heavy. The difficulty lies in knowing your back will fatigue faster than your quads. Take moving boxes for example. For the most part moving boxes aren't too heavy. If you only had to move one box, you could get away with performing the stoop lift to move that box inside. But continuing to use the stoop lift to move 30 or 40 boxes will tire your back well before you can even start to unpack! By starting from box one with the squat lift(which will feel awkward, and is all too easy to forget), you can save your back a lot of discomfort.
Monday, April 10, 2017
Muscles-Monday April 10th, 2017
I would be remiss to not talk about the actual sport of weightlifting during my project. As you can see in this clip, weightlifters use the squat lift while competing. This may seem to contradict my last post where I showed that the stoop lift takes less energy to lift the same box to the same height. So why don't weightlifters use the easier lift? Well, frankly, if they tried, the bar would never get off the ground! The squat lift takes more energy because it uses the quadriceps in your legs. This big muscle group takes more energy to activate, but is more powerful because


Thursday, March 30, 2017
Mathematical Analysis-Thursday March 30th, 2017
This is the equation for Garg's Method! But don't worry its less intimidating than it looks. The first section of the equation requires the summation of the energy of position multiplied by time. Position is basically standing or sitting. Since it takes certain energy to stand or sit this must be factored into the overall energy for the job. For both squats, the position is standing. The second part of the equation requires the summation of the change in energy of all tasks. For the lifts in my research this can be broken down to two motions: the lift and the arm raise. Since I lifted both boxes to the same height, the energy used in the arm raise will be the same for both the stoop and squat lift. The lift motion accounts for the energy until the load reaches 0.81 meters or hip height. Once the load reaches that height the arms begin lifting the load to its final height(in this case 1.42 meters). Calculating the energy for the squat and stoop lift requires two other equations that are impacted by initial height, final height, body weight, load weight, and sex(male or female). The equation for arm raise requires a very similar equation, but it isn't necessary here because it is the same for both lifts.
In my case, initial height was zero because I lifted the load from the ground. For these two equations, final height was 0.81 because I lifted the load above my hips. The variable S represents sex. Insert a 1 for a male subject and 0 for a female subject. The box that I lifted weighed 20 kg. I found time of lift by looking at how many frames of data were captured by the Vicon system. The stoop lift took longer at 353 frames or 3.53 seconds. The squat lift ended in 3.19 seconds. After calculating this all out, I found that the squat lift requires 18.629 kilocalories per minute while the stoop lift only requires 13.139 kcal/min. It is interesting to note that the stoop lift requires less energy despite being considered the inferior lift, but more on this next week!
In my case, initial height was zero because I lifted the load from the ground. For these two equations, final height was 0.81 because I lifted the load above my hips. The variable S represents sex. Insert a 1 for a male subject and 0 for a female subject. The box that I lifted weighed 20 kg. I found time of lift by looking at how many frames of data were captured by the Vicon system. The stoop lift took longer at 353 frames or 3.53 seconds. The squat lift ended in 3.19 seconds. After calculating this all out, I found that the squat lift requires 18.629 kilocalories per minute while the stoop lift only requires 13.139 kcal/min. It is interesting to note that the stoop lift requires less energy despite being considered the inferior lift, but more on this next week!
Monday, March 27, 2017
Garg's Method Introduction-Monday March 20th, 2016
First off, sorry for the late post. I wasn't able to travel to Prescott last week because of a spring snowstorm. I was supposed to start Garg's method last week. Garg's method is a way to "estimate metabolic energy expenditure rate for a job." This is will be the majority of my physiological analysis. This measures the rate at which energy is used for a task. Garg's method will normally be used in ergonomic research where a worker has to perform a task repeatedly throughout the day. This rate of energy production is measured in kilocalories per minute. For reference, an acceptable level of exertion for a worker over the course of a day is 5.2 kcal/min. For the next couple days, I will continue researching Garg's method and calculating the energy expenditure for my data. I will post my findings once I've had the opportunity for my advisor to review my calculations.
I also need to correct something from my last post. The program that I was using to graph and run profiles on my data wasn't actually using all the data. This means the graphs I posted in my last entry are wrong. Here are the corrected versions!
Squat:
Stoop:
I also need to correct something from my last post. The program that I was using to graph and run profiles on my data wasn't actually using all the data. This means the graphs I posted in my last entry are wrong. Here are the corrected versions!
Squat:
Stoop:
Friday, March 10, 2017
Static Equilibrium-Friday March 10th, 2017
This week I transitioned from working with the Vicon system, to researching what is actually happening during the lift. This involved looking at two things to start: physics, which I am very familiar with, and excel, which I am not familiar with. Using excel, I had to convert the units for my data, and organize all my data. There are more than 3,600 data points for just one of my lifts. After organizing the data, I transferred it into an analysis program. The analysis program showed us a bunch of information and graphed the analysis for me. We got some puzzling results, so we're still trying to make sure this is accurate. The first graph is the squat lift, the second is the stoop. As you can see, both are very similar and flat. What is puzzling is how flat both graphs are.
After this, I began analyzing my data for just a single frame of the data. This involves assuming a static equilibrium in order to solve for the force and torque at the elbow, shoulder and hip. By assuming a static equilibrium, all the forces and torques must cancel out to equal zero. This is something that I am familiar with doing. One new step that had to be taken was using a proportion to find the approximate weight of arm and wrist, as well as the length. Instead of trying to measure these things by hand, they can be approximated after only knowing the subject's height and weight. For example, take the height of the subject in centimeters and multiple it by (0.146 + 0.108) to find the length from elbow to hand. Because I'm 6'6"(about 198 centimeters) this value was 36.828 centimeters in my calculations. The last thing that must be found is the angle, relative to the horizontal, at the hip, shoulder and elbow. This can be found using the inverse of tangent and the x,y coordinates of the wrist, elbow, and shoulder. By taking the inverse tangent of the difference of the y coordinates, divided by the difference of the x coordinates, the angle can be found. This angle needs to be found in order to solve for torque. Next week, is spring break so I will not be posting, but the week after that, I'll start looking at what this information means, and what to do with it.
After this, I began analyzing my data for just a single frame of the data. This involves assuming a static equilibrium in order to solve for the force and torque at the elbow, shoulder and hip. By assuming a static equilibrium, all the forces and torques must cancel out to equal zero. This is something that I am familiar with doing. One new step that had to be taken was using a proportion to find the approximate weight of arm and wrist, as well as the length. Instead of trying to measure these things by hand, they can be approximated after only knowing the subject's height and weight. For example, take the height of the subject in centimeters and multiple it by (0.146 + 0.108) to find the length from elbow to hand. Because I'm 6'6"(about 198 centimeters) this value was 36.828 centimeters in my calculations. The last thing that must be found is the angle, relative to the horizontal, at the hip, shoulder and elbow. This can be found using the inverse of tangent and the x,y coordinates of the wrist, elbow, and shoulder. By taking the inverse tangent of the difference of the y coordinates, divided by the difference of the x coordinates, the angle can be found. This angle needs to be found in order to solve for torque. Next week, is spring break so I will not be posting, but the week after that, I'll start looking at what this information means, and what to do with it.
Thursday, March 2, 2017
33 Point Model! Thursday March 3rd, 2017

Thursday, February 23, 2017
Vicon Practice-February 23rd, 2017
This week I had the opportunity to run the Vicon system again. Being familiar with the system definitely helps a ton. During this practice, we did not encounter any new problems! After I controlled the system, I became the subject. I wore shorts so that the knee marker would not be interfered with, like the the first time we captured data, so we were able to capture more accurate data. Just like the first time we captured data, there was an issue with the system where it would switch the identification of the markers midway through the lift. This time we were actually able to correct the system without having to take another capture. This requires identifying the markers in the system multiple times, and it might have just been easier to take another capture, but nevertheless it worked. What we did differently this time was go through the recording frame by frame to see exactly where the markers switched identifications. When that happened, we would pause and rename the markers. Unfortunately this would usually result in the markers being misidentified later in the capture, so we would have to continue going through the capture frame by frame to cut out mistakes. This week was mostly about practicing what I had learned, so I don't have a ton of new information to share today, but I'm looking forward to next week!
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